Python, How To Send Data Over TCP
I need to create a simple server that listens for TCP connections. If it receives text on or off then it sends (echo) back success. The receiving part is wor
Solution 1:
Well i did it a day before following a very good tutorial, cant find the link but here is the code
client.py
import socket
host = socket.gethostname()
port = 12345 # The same port as used by the server
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((host, port))
s.sendall(b'Hello, world')
data = s.recv(1024)
s.close()
print('Received', repr(data))
For server
echo_server.py
import socket
host = '' # Symbolic name meaning all available interfaces
port = 12345 # Arbitrary non-privileged port
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((host, port))
print host , port
s.listen(1)
conn, addr = s.accept()
print('Connected by', addr)
while True:
try:
data = conn.recv(1024)
if not data: break
print "Client Says: "+data
conn.sendall("Server Says:hi")
except socket.error:
print "Error Occured."
break
conn.close()
Solution 2:
A better approach from the python 3 docs would be:
Server
import socketserver
class MyTCPHandler(socketserver.BaseRequestHandler):
"""
The request handler class for our server.
It is instantiated once per connection to the server, and must
override the handle() method to implement communication to the
client.
"""
def handle(self):
# self.request is the TCP socket connected to the client
self.data = self.request.recv(1024).strip()
print("{} wrote:".format(self.client_address[0]))
print(self.data)
# just send back the same data, but upper-cased
self.request.sendall(self.data.upper())
if __name__ == "__main__":
HOST, PORT = "localhost", 9999
# Create the server, binding to localhost on port 9999
server = socketserver.TCPServer((HOST, PORT), MyTCPHandler)
# Activate the server; this will keep running until you
# interrupt the program with Ctrl-C
server.serve_forever()
Client
import socket
import sys
HOST, PORT = "localhost", 9999
data = " ".join(sys.argv[1:])
# Create a socket (SOCK_STREAM means a TCP socket)
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as sock:
# Connect to server and send data
sock.connect((HOST, PORT))
sock.sendall(bytes(data + "\n", "utf-8"))
# Receive data from the server and shut down
received = str(sock.recv(1024), "utf-8")
print("Sent: {}".format(data))
print("Received: {}".format(received))
Hope it helps. Arturo
Solution 3:
If you need an endless/ continuous server connection you can use the following server code.
Server Code
import socket # Import socket module
port = 50000 # Reserve a port for your service every new transfer wants a new port or you must wait.
s = socket.socket() # Create a socket object
host = "" # Get local machine name
s.bind(('localhost', port)) # Bind to the port
s.listen(5) # Now wait for client connection.
print('Server listening....')
x = 0
while True:
conn, address = s.accept() # Establish connection with client.
while True:
try:
print('Got connection from', address)
data = conn.recv(1024)
print('Server received', data)
st = 'Thank you for connecting'
byt = st.encode()
conn.send(byt)
x += 1
except Exception as e:
print(e)
break
conn.close()
Client Code
import socket # Import socket module
import os
import re
s = socket.socket() # Create a socket object
port = 50000 # Reserve a port for your service every new transfer wants a new port or you must wait.
s.connect(('localhost', port))
x = 0
st = str(x)
byt = st.encode()
s.send(byt)
# send message for hundred times
while x<100:
st = str(x)
byt = st.encode()
s.send(byt)
print(x)
while True:
data = s.recv(1024)
if data:
print(data)
x += 1
break
else:
print('no data received')
print('closing')
s.close()
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