Pandas: Sort Innermost Column Group-wise Based On A Multilevel Column Excluding One Row Which Matches A Certain Substring
This is an extension to my previous question: Below df: In [225]: df = pd.DataFrame({'A': ['a'] * 12, ...: 'B': ['b'] * 12, ...: 'C': ['C1',
Solution 1:
Use Index.get_level_values
with str.contains
for test all
:
lvls = list(x.index.names[:-1])
print (lvls)
['B', 'C']
x[('tmp', 'tmp')] = pd.to_numeric(x[('E','a')].str.get('value'), errors='coerce')
x[('max','tmp')] = x.index.get_level_values(-1).str.contains('all')
x1 = x.sort_values(lvls + [('max','tmp'), ('tmp','tmp')])
print (x1)
E tmp max
A a tmp tmp
B C D
b C1 D1 {'value': '4', 'percentage': None} 4.0False
D2 {'value': 5, 'percentage': None} 5.0False
D3 {'value': 9, 'percentage': None} 9.0False
x:all:1 {'value': '9', 'percentage': None} 9.0True
C2 D3 {'value': 11, 'percentage': None} 11.0False
D1 {'value': 12, 'percentage': None} 12.0False
D4 {} NaN False0:1:all {'value': 33, 'percentage': None} 33.0True
C3 D1 {'value': 12, 'percentage': None} 12.0False
D3 {'value': '12', 'percentage': None} 12.0False
D2 {'value': 'N/A', 'percentage': None} NaN Falseall {'value': 24, 'percentage': None} 24.0True
And:
x2 = x.sort_values(lvls + [('max','tmp'), ('tmp','tmp')],
ascending=[True] * len(lvls) + [True, False])
print (x2)
E tmp max
A a tmp tmp
B C D
b C1 D3 {'value': 9, 'percentage': None} 9.0False
D2 {'value': 5, 'percentage': None} 5.0False
D1 {'value': '4', 'percentage': None} 4.0False
x:all:1 {'value': '9', 'percentage': None} 9.0True
C2 D1 {'value': 12, 'percentage': None} 12.0False
D3 {'value': 11, 'percentage': None} 11.0False
D4 {} NaN False0:1:all {'value': 33, 'percentage': None} 33.0True
C3 D1 {'value': 12, 'percentage': None} 12.0False
D3 {'value': '12', 'percentage': None} 12.0False
D2 {'value': 'N/A', 'percentage': None} NaN Falseall {'value': 24, 'percentage': None} 24.0True
Last remove helper columns:
x1 = x1.drop([('max','tmp'), ('tmp','tmp')], axis=1)
x2 = x2.drop([('max','tmp'), ('tmp','tmp')], axis=1)
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