Is There A Random Function In Python That Accepts Variables?

I'm attempting to create a simple dice roller, and I want it to create a random number between 1 and the number of sides the dice has. However, randint will not accept a variable.

Solution 1:

If looks like you're confused about the number of dice and the number of sides

I've changed the code to use raw_input(). input()is not recommended because Python literally evaluates the user input which could be malicious python code

import random
a=0final=0
working=0

rolls = int(raw_input("How many dice do you want to roll? "))
sides = int(raw_input("How many sides? "))

while a<rolls:
    a=a+1
    working=random.randint(1, sides)
    final=final+working

print "Your total is:", final

Solution 2:

you need to pass sides to randint, for example like this:

working = random.randint(1, int(sides))

also, it's not the best practice to use input in python-2.x. please, use raw_input instead, you'll need to convert to number yourself, but it's safer.

Solution 3:

Try randrange(1, 5)

Generating random numbers in Python

Solution 4:

random.randint accepts a variable as either of its two parameters. I'm not sure exactly what your issue is.

This works for me:

import random

# generate number between 1 and 6
sides = 6print random.randint(1, sides)