Why Are Decorator Functions Designed In The Way They Are?
Solution 1:
A decorator should return a function not the result of a function. In your first example, it returns a function ... In the second, it returns whatever your function f returns. - julien
Why second sample does not works?
Because you are calling the function on the return, you are not returning a function.
Why args,kwargs are "magically" appears if we are using a nested function?
They don't appear magically, we are declaring them, as in:
defdeco(*args, **kwargs):
These are generic, and will match any function signature (argument list). You don't have to call them
args
andkwargs
, that's just a convention, you could call themsharon
andtracy
.What can i do, to make 2nd sample work? Except nesting another function, ofcourse.
Well you don't say what you expect the 2nd sample to do. But I guess to turn it into a decorator then:
def func(f): return f
But that's not doing a lot!
By the way, it is usually a bad idea to override an existing Python builtin (sum
) - you have to have a very good reason for that. - cdarke
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